# Help with solving logarhythm problems

1. Jan 23, 2005

### wasteofo2

How would I go about solving a problem like this?

Given $$log_c 3 = 1.875$$ and $$log_c 2 = 1.214$$ evaluate $$log_c {\sqrt{12}$$

What method would I have to use to solve a question like this?

2. Jan 23, 2005

### dextercioby

$$\log_{c}\sqrt{12}=\log_{c}(12)^{\frac{1}{2}}=\frac{1}{2}\log_{c}12$$

Take it from here.
Use the data & the properties of the "log" function.

Daniel.

3. Jan 23, 2005

### learningphysics

4. Jan 23, 2005

$$log_c 2 \sqrt 3 = log_c 2 + log_c \sqrt 3$$

you know what $$log_c 2$$ is

Thanks a lot for your kind words

NOTE: should be $$\sqrt 3$$ not $$\sqrt 2$$ for second part of addition. For some reason it will not let me change it.

Last edited: Jan 23, 2005
5. Jan 23, 2005

### NeutronStar

Start by setting it equal to itself:
$logarhythm = logarhythm$

Take the antilog of both sides:
$arhythm = arhythm$

Replace $hy = i[/tex]: [itex]arithm = arithm$

Take the log of both sides again and you're done:
$logarithm = logarithm$

:tongue: :uhh: