# Help with solving logarhythm problems

1. Jan 23, 2005

### wasteofo2

How would I go about solving a problem like this?

Given $$log_c 3 = 1.875$$ and $$log_c 2 = 1.214$$ evaluate $$log_c {\sqrt{12}$$

What method would I have to use to solve a question like this?

2. Jan 23, 2005

### dextercioby

How about
$$\log_{c}\sqrt{12}=\log_{c}(12)^{\frac{1}{2}}=\frac{1}{2}\log_{c}12$$

Take it from here.
Use the data & the properties of the "log" function.

Daniel.

3. Jan 23, 2005

### learningphysics

courtigrad, following the previous advice dextericoby previously gave me... Your post was great, and your approach to the problem was fine. Don't delete your great posts!

4. Jan 23, 2005

### courtrigrad

$$log_c 2 \sqrt 3 = log_c 2 + log_c \sqrt 3$$

you know what $$log_c 2$$ is

Thanks a lot for your kind words

NOTE: should be $$\sqrt 3$$ not $$\sqrt 2$$ for second part of addition. For some reason it will not let me change it.

Last edited: Jan 23, 2005
5. Jan 23, 2005

### NeutronStar

Start by setting it equal to itself:
$logarhythm = logarhythm$

Take the antilog of both sides:
$arhythm = arhythm$

Replace $hy = i[/tex]: [itex]arithm = arithm$

Take the log of both sides again and you're done:
$logarithm = logarithm$

:tongue: :uhh:

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