1. The problem statement, all variables and given/known data A uniform tube, 60.0cm long, stands vertically with its lower end dipping into water. When the lenght above water is 14.8cm, and again when it is 48.0cm. the tube resounds to a vibrating fork of frequency 512Hz. Find the lowest frequency to which the tube will resound when it is open at both ends 2. Relevant equations 3. The attempt at a solution When the tube is open at both end, the fundamental frequency f1 is given by: f1=v/(2x0.6) From the given condition 512 = （2n1-1)v/(4x0.148) 512 = (2n2-1)v/(4x0.48) How can I find the velocity from the abve two equations?