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Help with surjectivity proof

  1. Jul 15, 2010 #1
    The problem is:

    Prove that the function, f:(-1,1)->R given by f(x)=x/(1-x^2) is surjective

    The way I have learned to prove a function is surjective is to solve for an x that is given explicitly in terms of y and then plug it into the equation and show that y=y, and thus any y in the codomain will have a corresponding x such that f(x)=y. But in this problem I can't for the life of me seem to solve for an x explicitly in terms of y, I'm assuming it can't be done. I solved for an x explicitly in terms of x and y, but I'm not sure what that gets me. There must a more intuitive, simple way to prove it.

    I mean I understand why its surjective since at -1 and 1 the function diverges to -∞ and ∞ respectively so every value in R will have some corresponding input within the open interval (-1,1), but I can't figure out how to prove it without employing facts about the continuity of polynomials and limits etc. which I don't believe I am allowed to use.
  2. jcsd
  3. Jul 15, 2010 #2
    Let's try once again:
    [tex]y - x^2y=x[/tex]
    [tex]y x^2 + x - y = 0[/tex]
    Now, recall the quadratic formula:
    [tex]x=\frac{1}{2y}(1\pm \sqrt{1+4y^2})[/tex]
    for [tex]y\neq 0[/tex]. But solution with "+" is clearly greater than one or less than -1.
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