A string is wrapped several times around the rim of a small hoop with radius 0.0800 meters and mass 0.344 kg. If the free end of the string is held in place and the hoop is released from rest calculate the tension in the string while the hoop descends as the string unwinds. Give your answer in Newtons to the third decimal place.
[tex]\Sigma[/tex] Torque = (Tension)*(Radius) = (Impulse)*(angular acceleration) = (1/2)*(Mass)*(Radius2)*(angular acceleration)
The Attempt at a Solution
I tried to derive the solution down to, Tension = (1/3)*(mass)*(g) but I am not returned with the correct answer. I calculated 1.12 N and the correct answer states 1.686 N