if \epsilon_{ijk} P_{kj}=0 how do we show P_{ij}=P_{ji}?
Apr 26, 2009 #1 latentcorpse 1,444 0 if [itex]\epsilon_{ijk} P_{kj}=0[/itex] how do we show [itex]P_{ij}=P_{ji}[/itex]?
Apr 26, 2009 #3 latentcorpse 1,444 0 do you mean just substitute in numbers and see what happens because that works - i was just wondering if i could do it without explicitly using numbers (i.e. all of it in index notation).
do you mean just substitute in numbers and see what happens because that works - i was just wondering if i could do it without explicitly using numbers (i.e. all of it in index notation).
Apr 26, 2009 #4 dx Homework Helper Gold Member 2,130 41 For i = j, clearly Aij = Aji, so you only need to check the cases in which i ≠ j. For example, setting i = 1 in εijkAkj = 0, you get ε123A32 + ε132A23 = A32 - A23 = 0 ⇒ A32 = A23. You just need to do the same with i = 2 and i = 3.
For i = j, clearly Aij = Aji, so you only need to check the cases in which i ≠ j. For example, setting i = 1 in εijkAkj = 0, you get ε123A32 + ε132A23 = A32 - A23 = 0 ⇒ A32 = A23. You just need to do the same with i = 2 and i = 3.