• Support PF! Buy your school textbooks, materials and every day products Here!

Help with the Carnot Cycle

  • #1
107
0

Homework Statement


its part VI) of a big problem, where:

0.12 moles of argon (40) undergoes the cycle abca described in the graph. Process ab lies on a 540k isotherm.

In the previious 5 sub problems, i figured that:

Tc=270k
Qbc=670J (lost)
Qca=400J (added)
Wab=370J
Wabca=100J


The PV diagram has points a,b and c where:

a=(1.5X10-3, 3.6X105)
b=(3X10-3, 1.8X105)
c=(1.5X10-3, 1.8X105)







Homework Equations



Q=mc[itex]\Delta[/itex]T

[itex]\Delta[/itex]U=Q+W

[itex]\epsilon[/itex]=1-Qout/Qin=1-Tlow/Thigh

The Attempt at a Solution


So it's basically using Qabca to find the efficiecy. The thing is that im not sure what to use for the Qs.
 

Answers and Replies

  • #2
374
1
What is Qs supposed to represent? I don't see it in your problem statement.
 
  • #3
107
0
What is Qs supposed to represent? I don't see it in your problem statement.
it's a plural for Q, I am not sure what to use for Qin and Qout
 
  • #4
374
1
Remember this is NOT a carnot cycle. η= 1- Qout/Qin There is also a Qin between A and B. Do you know what it is? It is the Qout/ the Total Qin.
 

Related Threads on Help with the Carnot Cycle

  • Last Post
Replies
2
Views
965
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
4
Views
6K
  • Last Post
Replies
2
Views
695
  • Last Post
Replies
2
Views
665
  • Last Post
Replies
3
Views
553
  • Last Post
Replies
1
Views
729
  • Last Post
Replies
3
Views
985
Top