# Help with this integral

1. Oct 13, 2006

### meee

$$\int \frac{1}{x\log_{e} 4x} dx$$

wow i finally got latex to work

ok... so i did it on a text and got $$\log_{e}(\log_{e}4x)+c$$

now i did it and got $$\frac{1}{4}\log_{e}(\log_{e}4x)+c$$

which is right?

what is the derivative of $$\log_{e}4x$$ ?

Last edited: Oct 13, 2006
2. Oct 13, 2006

do you mean $$\int \frac{1}{x\ln 4x} dx$$? Use the substitution $$u = \ln 4x$$.

3. Oct 13, 2006

$$\log_{e} 4x = \ln 4x$$. Can you take the derivative of that now?

4. Oct 13, 2006

### meee

ohhhh.... is it $$\frac{4}{4x} = \frac{1}{x}$$ ?

5. Oct 13, 2006