I have gotten from this equation: y=3x into its polar form by substituting(adsbygoogle = window.adsbygoogle || []).push({});

x= r cos (theta) and y=r sin (theta) to get me here:

r sin (theta) = 3r cos (theta)Substitute and simplify.

r sin (theta) - 3r cos (theta) = 0Subtract 3r cos (theta) from both sides.

r [sin (theta) - 3 cos (theta)] = 0Factor out r from the equation.

Now I set both equal to zero like this...

r = 0 or sin (theta) - 3 cos (theta) = 0

I am assuming r = 0 is included in the graph of the second equation. So the only solution to the original problem comes from solving the second equation for Theta --->

sin (theta) - 3 cos (theta) = 0

arctan (3) =1.2490 radians

Is 1.2490 radians the correct solution to the original question of convert y=3x into polar form?

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# Help with this polar equation please.

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