Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Help with this polar equation please.

  1. Dec 7, 2007 #1
    I have gotten from this equation: y=3x into its polar form by substituting
    x= r cos (theta) and y=r sin (theta) to get me here:



    r sin (theta) = 3r cos (theta) Substitute and simplify.

    r sin (theta) - 3r cos (theta) = 0 Subtract 3r cos (theta) from both sides.

    r [sin (theta) - 3 cos (theta)] = 0 Factor out r from the equation.

    Now I set both equal to zero like this...

    r = 0 or sin (theta) - 3 cos (theta) = 0



    I am assuming r = 0 is included in the graph of the second equation. So the only solution to the original problem comes from solving the second equation for Theta --->

    sin (theta) - 3 cos (theta) = 0

    arctan (3) = 1.2490 radians

    Is 1.2490 radians the correct solution to the original question of convert y=3x into polar form?
     
  2. jcsd
  3. Dec 7, 2007 #2

    Office_Shredder

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    That might be the right answer to the question of what angle is formed between the line y=3x and the x-axis, but just "1.2490 radians" isn't a polar form of anything, it's just a number. An answer like "theta=1.249" might look better, but keep in mind you're missing the half of the line that goes through the third quadrant (as traditionally r is taken to be non-negative)
     
  4. Dec 7, 2007 #3
    Thanks for your help. Office Shredder. Are either of these possible as polar points

    (0,1.249 rad) , (infinity, 1.249 rad)

    because I am thinking since r = 0 it cannot possibly be a line like y=3x. Convert the radian angle I found into a polar point that extends infinitely into the I and III Quadrants like the rectangular line equation.
     
    Last edited: Dec 7, 2007
  5. Dec 7, 2007 #4
    Remember that polar coordinates are not the best for graphing straight lines, they are better with curves.

    you have, sin (theta) - 3 cos (theta) = 0. from here, you can get
    sin (theta) = 3 cos (theta), divide both sides by cos (theta)
    tan (theta) = 3

    Now think about all the (r, theta) that satisfy this equation. Well no matter what the r is the tan of theta has to be equal to 3. So as long as the angle formed with the origin is 1.249 rad, then the point (r, theta) is valid. The set of all (r, theta) solutions is the same as your graph of y = 3x.

    HTH
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Help with this polar equation please.
Loading...