# Homework Help: Help with trigonometric proof

1. Jan 17, 2012

### matthewd49

1. The problem statement, all variables and given/known data

basically i have this proof to do where (cot5x * [trigonometric function]5x)/csc6x = 5/6 and i have to prove it equals 5/6

2. Relevant equations

but what i can't remember about the problem is the second function. i've tried plugging in all of them and using a made up value of x = 10 just to see if i could figure out what the function i can't remember it is but i haven't had any luck.

cos(0) = 1
sin(x)/x = 1

3. The attempt at a solution

the closest i've come to what may be the missing function is when i plug in sin5x but i get a number that is approximately .85 and not .833.

well if i could figure out the function i know to set it up like this ((cos5x/tan5x) * [unknown function]5x)/(1/sin6x)

2. Jan 18, 2012

### lanedance

are you evaulating a limit as x tends to zero?

in general, for arbitrary $x \neq 2 n\pi$
$$\frac{sin(x)}{x}\neq 1$$

And in fact when $x =n\pi$ the function is undefined, but the limit exists, for example
$$\lim_{x \to 0}\frac{sin(x)}{x}= 1$$

3. Jan 18, 2012

### SammyS

Staff Emeritus
Hello matthewd49. Welcome to PF !

How sure are you that the expression was of the form $\displaystyle\frac{\cot(5x)\text{trig}(5x)}{\csc(6x)}\,,$ where trig(θ) is one of the trig functions?

This expression is equivalent to $\displaystyle\frac{\cos(5x)\text{trig}(5x)\sin(6x)}{\sin(5x)}\,,$ also $\displaystyle\frac{\text{trig}(5x)\sin(6x)}{\tan(5x)}\,.$

You also have $\frac{\displaystyle\frac{\cos(5x)}{ \tan(5x)}\text{trig}(5x)}{\displaystyle\frac{1}{ \sin(6x)}}\,,$ which is not equivalent to the above expression.

Your last expression is equivalent to $\displaystyle\frac{\cos^2(5x)\text{trig}(5x)\sin(6x)}{\sin(5x)}\,.$

BTW: $\displaystyle\lim_{x\,\to\,0}\frac{\sin(6x)}{\sin(5x)}=\frac{6}{5}\,.$ This leads me to believe that your mystery function is $\sec(5x)\,.$

4. Jan 18, 2012

### matthewd49

hi guys thanks for all your help. i found out the missing function was actually sec5x and then found out afterwards that they had presented the problem wrong and wanted me to prove that said function was = to 6/5, not 5/6. that made it a much easier problem which i quickly finished. thanks for all of your help though, you guys are awesome!