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Help with understanding force between two current carrying coils

  1. Sep 21, 2005 #1

    Arv

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    Hi

    I am currently involved in building a linear motor which is based around the coil gun principle. I am having trouble understanding the equation for force used to desribe the coilgun's action.

    namely:
    Fx = I1*I2*dM/dX

    Fy = I1*I2*dM/dX

    Here we are considering two coils of wire, with an rapidly
    changing current allowed to flow through one of the coils (The active coil)which in turn induces a current in the nearby 'passive' coil (via Lenz Law). So I1 is the active current and I2 is the passive current.

    So bascially u end up with two magnetic poles with same polarity next to each other and there is a repulsion action. If the vertical movement is constrained, you are left with horizontal thrust which is what the linear motor makes use of.

    I can relate this force equation to physics textbooks' description of force betweentwo parallel current carrying conductors which uses the Lorentz Force equation (F = I*L*B) and Magnetic Field near straight wire (B = mu*I/(2*PI*R) to arrive at F = (mu*I1*I2)/(2*PI*D).

    I don't how to explain the dM/dX part.

    Can someone help me get from the F = I*L*B description to the
    F = I*dM/dX description.

    The M in dM/dX is the mutual inductance which is the coefficient that
    describes the linking flux between the two coils. Why should the force
    depend on a gradient in mutual inductance? Can someone offer
    an intuvitive explanation for this or perhaps provide a sketch of a proof
    which I can work on?

    Thanks
    Arv
     
  2. jcsd
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