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Forums
Engineering
General Engineering
Help With Understanding Hooke's Law
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[QUOTE="RPinPA, post: 6071881, member: 651116"] The original length is a constant of the spring. So let's say we have ##(F/A) = R * (x/L)## where [I]R[/I] = some constant of proportionality, [I]x[/I] = change in length and [I]L =[/I] original length. Then ##F = (RA/L)x## and since [I]R[/I], [I]A[/I] and [I]L[/I] are constants of the spring, we can treat the whole expression in parentheses as a constant. Call it ##k##, so ##F = kx##. The fact that the "spring constant" depends on the original length of the spring tells you something about how the spring will behave, what the new constant of proportionality will be, if you cut the spring in half. [/QUOTE]
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Help With Understanding Hooke's Law
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