There are three forces, each of magnitude 5.00 N applied to a particle at O in the directions shown in Fig. 1. List the components of the individual forces F1, F2, and F3. Obtain the x and y components of the resultant of the three forces, R = F1 + F2 + F3 and the magnitude of R and its direction by giving the angle to one of the axes.
F1 vector is right on the x-axis and its direction is east.
F2 vector is 30 degrees from +y. It is between north and west.
F3 vector is 30 degrees from -y. It is between south and west.
The Attempt at a Solution
For the F3 vector, I did sine 30 = x/5 and I got 2.5. Then I used cosine and I got 4.33 for the other side. I did the same process for the F2 vector.
So my components were:
F3 (-2.5, -4.33)
F2 (-2.5, 4.33)
F1 (5, 0)
I add the component up to get R and I get 0 for the components and for the vector of R. Did I do something wrong? Or is this correct?