# Help with vectors?

1. Mar 11, 2014

### jesstryin

1. The problem statement, all variables and given/known data

Hi everyone, my problem is this:

Darryl drives his load of tomatoes 14.0 km [E], 6.0 km [N], 12.0 km [ N 15° E], and then 2.0 km [N 65° E]. This takes him 42 minutes.

a) Calculate Darryl's distance and displacement. Draw a diagram and show your work.
b) Calculate Darryl's average speed and average velocity (record your answer in m/s).

2. Relevant equations

sinb/b =sinC/C

3. The attempt at a solution

A. 14 km + 6.0 km + 12.0 km + 2.0 km = 34 km
Total Distance is 34 km = 34,000 m

D (east) = 14 + 12 * sin15 + 2 * sin65 = 18.9 km

D (north) = 6 + 12 * cos15 + 2 * cos65 = 18.4 km

C2 =√ a2 + b2
D = √(18.9km² + 18.4km²)
= 26.4 km

My problem is that I think I miscalculated the displacement (east), for the speed and velocity calculation I did this:

B.
Vav (speed) = 34km / 42 min = 34,000 m / 2520 s
Vav= 13.49 or 13.5 m/s

Vav = 26.4 km / 42 min = 26,400 / 2520
Vav (velocity) = 10.47 or 10.5 m/s

I just need clarification for displacement, so that I can accurately calculate the velocity.

2. Mar 11, 2014

### Staff: Mentor

Hi jesstryin. Welcome to Physics Forums.

3. Mar 11, 2014

### jesstryin

Thank you! Could you let me know if I got the answer correct for displacement, I feel like I'm missing a step and need the displacement to calculate the right velocity. Thanks so much!

4. Mar 11, 2014

### Staff: Mentor

Your displacement magnitude calculation is correct.

Don't forget that vector quantities are specified by a magnitude and a direction.

5. Mar 11, 2014

### jesstryin

So, is the answer for displacement 26.4 km N 54.9 degrees E ? Or is it 26.4 km E 54.9 degrees N ? I think it is the former, but I am not sure.

Thank you for all the help I appreciate it!

6. Mar 11, 2014

### Staff: Mentor

I believe this link explains that.

http://www.compassdude.com/compass-units.shtml