Help with view factors

  • Thread starter princejan7
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  • #1
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Homework Statement


I found the values ##F_{3\rightarrow(1+2)}=0.32## and ##F_{1\rightarrow3}=0.25##
I now want to find ##F_{2\rightarrow3}##

Homework Equations


Reciprocity relation
##A_iF_{i\rightarrow j}=A_jF_{j\rightarrow i}##

The Attempt at a Solution


Using the reciprocity relation to find ##F_{(1+2)\rightarrow3}##
##A_3F_{3\rightarrow(1+2)}=A_{(1+2)}F_{(1+2)\rightarrow3}##
##3(0.32)=6F_{(1+2)\rightarrow3}##
##F_{(1+2)\rightarrow3}=0.16##

Using that to find ##F_{2->3}##:
##F_{1\rightarrow3}+F_{2\rightarrow3}=0.16##
##0.25+F_{2\rightarrow3}=0.16##
##F_{2\rightarrow3}=-0.09##

But I get a negative value
 

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Answers and Replies

  • #2
haruspex
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##F_{(1+2)\rightarrow3}=0.16##
##F_{1\rightarrow3}+F_{2\rightarrow3}=0.16##
I don't think ##F_{(1+2)\rightarrow3}=F_{1\rightarrow3}+F_{2\rightarrow3}##
 

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