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- Thread starter Forgo
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- #1

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- #2

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By giving you the weight of the object, they are indirectly giving you it's mass ([tex]W=mg[/tex]).

Hope that helps,

-Jason

- #3

nautica

Just set ccw equal to cw and go from there.

Nautica

- #4

- 3,106

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- #6

nautica

FYI

There is a section on homework help. Scroll down.

Nautica

There is a section on homework help. Scroll down.

Nautica

- #7

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If you take a 10kn seesaw which is 10 metres long but the fulcrum (pivot) is placed 6 metres from one end then the seesaw will fall towards the 6 metre end as the "moment" (engineering term) will be greater acting about the centre of thats sides mass i.e. 6kn x 3 metres = 18knm, where as the 4 metre side would be 4kn x 2 metres giving 8knm. To balance this out we need an extra 10knm on the 4 m side so if you know the weight of the kid say 4 kn then we can find the position for equilibrium (balance) by dividing the required additional moment 10knm, by the kid i.e. 10knm divided by 4kn giving a distance of 2.5 metres from the fulcrum on the 4 metre side of the seesaw.

Just in case she has a crafty teacher

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