- #1

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i used z=a/2 but have a sneaky feeling its' meant to be [itex]\frac{a}{\sqrt{2}}[/itex]

can anyone help?

- Thread starter latentcorpse
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- #1

- 1,444

- 0

i used z=a/2 but have a sneaky feeling its' meant to be [itex]\frac{a}{\sqrt{2}}[/itex]

can anyone help?

- #2

- 105

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Are you looking at the top half of a solid sphere centered at the origin with radius a?

- #3

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basically i have an expression for the electric field on the z axis as the hemispherical surface is charged and it asks me to find the value of the electric field at the centre of the hemisphere - what z value should i use?

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