Henry's Law Question

  • #1

Homework Statement


How much water would be needed to completely dissolve 1.48L of the gas at a pressure of 730torrand a temperature of 28∘C? A gas has a Henry's law constant of 0.190M/atm

Homework Equations


S=kH * Pgas

The Attempt at a Solution


730 torr= .960526316 atm

S=(.190M/atm)(.960526316 atm)
S= .1825 M
.1825 mol = X = .2701 moles
1 L 1.48L

After solving that part I don't understand how to get liters of water. Maybe PV=nRT... but I tried that and I got the answer wrong.
 

Answers and Replies

  • #2
Borek
Mentor
28,702
3,190
How many moles of the gas? How many dissolved per liter of water?
 
  • #3
.2701 moles of the gas
 
  • #4
Borek
Mentor
28,702
3,190
No. 1.48 L of gas at 730 torr and 28°C is not 0.27 moles.
 

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