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## Homework Statement

How much water would be needed to completely dissolve 1.48L of the gas at a pressure of 730torrand a temperature of 28∘C? A gas has a Henry's law constant of 0.190M/atm

## Homework Equations

S=kH * Pgas

## The Attempt at a Solution

730 torr= .960526316 atm

S=(.190M/atm)(.960526316 atm)

S= .1825 M

.1825

__mol = X__= .2701 moles

1 L 1.48L

After solving that part I don't understand how to get liters of water. Maybe PV=nRT... but I tried that and I got the answer wrong.