Given the following information: Fe2O3 + 3CO -> 2Fe + 3CO2 Heat = -28.0 kJ 3Fe + 4CO2 -> 4 CO + Fe3O4 Heat =-12.5 kJ FInd the heat for the following reaction: Fe2O3 + CO -> CO2 + Fe3O4 Balance the equation first and remember to include the correct units. 3Fe2O3 + CO -> CO2 + 2Fe3O4 Fe2O3 + 3CO --> 2Fe + 3CO2 H = -28 kJ 2(3Fe + 4CO2 --> 4CO + Fe3O4 H = -12.5 kJ) 3(Fe2O3 + 3CO --> 2Fe + 3CO2 H = -28.0 kJ) 6Fe + 8CO2 --> + 2 Fe3O4 H = -25.0 kJ 3Fe2O3 + 9CO --> 6Fe + 9CO2 H = -84.0 6Fe + 8CO2 --> 8CO + 2Fe3O4 H = -25.0 kJ Thus, 3Fe2O3 + CO -> CO2 + 2Fe3O4 and H = -109 kJ?? Use the presented information to find the H for: N2 + O2 ->2NO 1/2 N2 + O2 -> NO2 H = 32.16 4NO + 2O2 ->4NO2 H = -227.9 1/2 N2 + O2 -> NO2 H = 32.16 1/2 (4NO + 2O2 ->4NO2 H = -227.9) 2(1/2 N2 + O2 -> NO2 H = 32.16) 2NO2 --> 2NO + O2 H = +113.95 N2 + 2O2 --> 2NO2 H = 64.32 2NO2 --> 2NO + O2 H = +113.95 Thus, N2 + O2 ->2NO and H = 178.27 = 178.3 ?? I suppose the units are kJ even if they didn't state which units are used? Thanks.