Hess's Law and Ionization Energy

  • #1

Homework Statement



I1, = 786 kJ molG1 I5 = 16,091 kJ molG1
I2 = 1577 kJ molG1 I6 = 19,784 kJ molG1
I3 = 3232 kJ molG1 I7 = 23,766 kJ molG1
I4 = 4355 kJ molG1 I8 = 29,251 kJ molG1

Determine the energy required in kJ molG1 for the following process:
M(g)^+ ------> M^5+(g) + 4 e



The Attempt at a Solution



I saw the solution sheet and it says "E = 25,255 kJ/mol (Sum of I2, I3, I4 and I5) Use Hess’s Law"

But why is it I2 to I5 and I thought it should be (products - reactants)
which I thought is I6 - I2. Could someone explain to me?

Thanks
 

Answers and Replies

  • #2
Borek
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Write reaction equation for each Ix.
 
  • #3
I1 =M(g) ---> M^+(g) +e
I2= M+(g) ----> M2+ + e
I3 =M2+ ----> M3+ + e
I4 = M3+ ----> M4+ +e
I5 = M4+ ----> M5+ + e
I6 =M5+ ----M6 + +e

What's next?
 
  • #4
Did I do them right?
 
  • #5
Borek
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OK, now, which reactions have to be combined?
 
  • #6
I still dont understand. What I'm thinking is still I6 - I1...
 
  • #7
Borek
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I1 is about starting with Mg(0) - do you have Mg(0) in the process?
 
  • #8
No, I1 wont be in the process.
 
  • #9
Borek
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What if I tell you that I6 is NOT Mg(0) -> Mg6+?
 
  • #10
Oh in my other previous post it should I6-I2. For I6 isnt it I6 =M5+ ----M6 + +e?
 
  • #11
Borek
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Yes, I6 is Mg5+ -> Mg6+.

What reactions are needed to go from Mg(0) to Mg2+? Is I1 enough, or do you need I1 AND I2?
 
  • #12
I'm thinking I1 and I2 is needed.
 
  • #13
Borek
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Yes, you need both. Now, which ones do you need to go from Mg+ to Mg5+?
 

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