Heurestic approach EFE - why are there 10 DOF?

  • A
  • Thread starter binbagsss
  • Start date
  • #1
binbagsss
1,236
10
TL;DR Summary
Some sources state we seek 10 dof ( and so ofc this is a symmetric two index tensor.


My question is why we seek 10 dof in the first place ?


Many thanks
Some sources state we seek 10 dof ( and so ofc this is a symmetric two index tensor.


My question is why we seek 10 dof in the first place ?


Many thanks
 

Answers and Replies

  • #3
New Simplicio
15
0
The number of equations is because in General Relativity there are four dimensions of spacetime.
 
  • #4
Daverz
1,001
74
The metric is symmetric, so there are only 10 independent equations out of 16. That accounts for 6 degrees of freedom. The remaining 4 degrees of freedom are to allow for arbitrary coordinate transformations.
 
  • #5
41,269
18,896
The metric is symmetric, so there are only 10 independent equations out of 16. That accounts for 6 degrees of freedom. The remaining 4 degrees of freedom are to allow for arbitrary coordinate transformations.

No, this is not correct. First, 10 independent equations does not account for 6 degrees of freedom. Second, 4 degrees of freedom is not enough to allow for arbitrary coordinate transformations.
 
  • #6
41,269
18,896
In the absence of any references, this thread is closed.
 

Suggested for: Heurestic approach EFE - why are there 10 DOF?

Replies
3
Views
1K
Replies
1
Views
611
Replies
3
Views
657
Replies
29
Views
1K
Replies
28
Views
1K
Replies
2
Views
435
Replies
14
Views
786
Replies
0
Views
628
Replies
1
Views
508
Top