Equilibrium on Incline: Solving for Fn with Fg and Θ | 3.80 kg Block | N Units

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In summary, a 3.80 kg block is in equilibrium on an incline of 38.4 degrees with an acceleration of gravity of 9.81 m/s^2. The question is asking for the normal force of the incline on the block, which can be found using the equations FgsinΘ=mgsinΘ and FgcosΘ=mgcosΘ. The correct answer is 29.21 N. There may have been a mistake in the calculation process, as the student initially got an incorrect answer of 28.49 N.
  • #1
KB94
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Homework Statement



A 3.80 kg block is in equilibrium on an incline
of 38.4◦.
The acceleration of gravity is 9.81 m/s2 .
What is Fn of the incline on the block?
Answer in units of N.

Homework Equations





The Attempt at a Solution



FgsinΘ=mgsinΘ=3.8*9.81*sin38.4°=24.04
FgcosΘ=mgcosΘ=3.8*9.81*cos38.4°=28.49

This is from an online assignment. The second equation should've given me the correct value, but when I input the answer, the system tells me it's incorrect. Could anyone enlighten me on this situation? Maybe I'm doing something wrong. Please I would appreciate a quick reply. Thank you.
 
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  • #2
I get 29.21.
 
  • #3
Oh hehe I must've made a mistake while calculating. Thank you very much. It's correct.
 
  • #4
KB94 said:
FgsinΘ=mgsinΘ=3.8*9.81*sin38.4°=24.04
FgcosΘ=mgcosΘ=3.8*9.81*cos38.4°=28.49

I get the same as ideasrule. You have both of your answers off, so there must be something wrong with the way you are typing them into the calculator.

Also, I'm not sure what you mean by FgcosΘ=mgcosΘ. What is Fg? You should probably write it as:

F=mgcosΘ
 

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