1. The problem statement, all variables and given/known data Falls result in hip fractures are a major cause of injury and even death to the elderly. Typically, the hip's speed at impact is about 2.0 m/s. If this can be reduced to 1.3 m/s or less, the hip will usually not fracture. One way to do this is by wearing elastic hip pads. If the typical pad is 5.0 cm thick and compresses by 2.0 cm during the impact of a fall, what constant acceleration (in m/s^2 and in g's) does the hip undergo to reduce its speed from 2.0 m/s to 1.3 m/s? Report Abuse 2. Relevant equations V^(2)=Vo^(2) + 2A(X-Xo) 3. The attempt at a solution (1.3m/s)^(2)=(2.0m/s)^(2) + 2A(0.05m-0.02m) A= -38.6m/s^(2) [EDIT] sorry! Is this right? Thanks!