Determine the power dissipated in the 9.0 resistor in the circuit shown in the drawing. (R1 = 3.0 , R2 = 9.0 and V1 = 12 V.)(adsbygoogle = window.adsbygoogle || []).push({});

ok here's my problem..... I've found the current throughout to be 2.261 a.....

now if i use that to find the voltage in the 9 ohm resistor, i get a voltage bigger than my batteries voltage!

i'm completely confused on where to go with that current to get to power.....

any help on what exactly my next step is would be appreciated. thank you in advance!:shy:

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# Hmmm power in a parallel/series circuit

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