A 259 g hockey puck is sliding on ice with a speed of 5.34 m/s hits a wall at an angle of 34.8° to the wall and bounces back at the same angle with the same speed.
If the wall and the hockey puck are in contact for 11.3 ms, find the magnitude of the impulse on the puck.
change in p = J
J=F(change in t)
J is impulse force
The Attempt at a Solution
1st attempt: I tried just multiplying my velocity and mass to get momentum, that failed
2nd attempt: I tried resolving my components
X: (0.259)(5.34)(sin34.8)=0.789 kg m/s
Y: (0.259)(5.34)(cos34.8)=1.14 kg m/s
vf = sqrt((0.789)^2 + (1.14)^2)
= 1.39 m/s
= 0.360 kg m/s
p=ma = J therefore J=0.360 kg m/s
I'm really not sure what I'm doing wrong, could someone pls help?