# Home Work Check / Algebra

• 1babelove
In summary, the student attempted to solve an equation for homework, but had some problems. The student asks the expert if they can look at the problems, and the expert agrees.f

## Homework Statement

5/8x + 1/16x= 9/16 + x

## The Attempt at a Solution

10x+ x = 9+16
11x=9+16x
-5x=9
x= - 9/5
x =- 1.8

Is this correct. I am trying to make sure I am in the right direction

Also is f(x) = 2x^2-2x
f(0) = I got )
f(-1) I got 4
f(2) Igot 4

Is this correct also..

I need to make sure that this one is correct also

What is the domain of g(x) = 3/5-3x
I got that x is not equal to 5/3.

I hope I got all these right...

I think you have a typo for f(0), what did you get? I agree with your answer for f(-1) and f(2). If part 1 has the x upstairs in the fractions like,
(5*x)/8 + (1*x)/16 = 9/16 + x
then I agree with your answer. But not if it is downstairs like,
5/(8*x) +1/(16*x) = 9/16 +x

I'm not sure I agree with your domain of g(x). What is your reasoning for 5/3?

Because I can not see g(x) = 3/5-3x answers being either a.not equal to 3, b. equal to 0. or c x greater than or equal to 5/3..My head is spinning numbers maybe I am wrong

and for f(0) = 2x^2 -2x when you mutiply be zero the answer is 0..right?

The problem with the domain question is that we were not sure if you meant
$$g(x) = \frac{3}{5 - 3x}$$
or
$$g(x) = \frac{3}{5} - 3x.$$

It looks like you meant the former. (That is why it's helpful to learn LaTex. ) Anyway, you're right -- the domain is
$$x \neq \frac{5}{3}.$$

01

I have a some more problems that I want checked will you be willing to look at them, please.

Just post them in a new thread. Also, if you're seriously unsure whether your answer is correct or not, point out which steps you weren't sure about when you were solving the question.