Determine the acceleration of rope hoist

In summary, Gameguru's problem is to determine the acceleration of a 72 kg man who ties one end of a nylon rope around his waist and throws the other end over a branch of a tree. The only force that he needs to concern himself with is the vertical motion. If he lets go of the free end of the rope, the net downward force on him would be 2T+mg=ma. However, if he pulls on the rope, his weight is distributed to the force of T1, which doesn't account for the upward force on him due to the "pully" of the turn-around of the limb. By solving for a, Gameguru finds that the acceleration is 0.14 m/s2.
  • #1
gameguru
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Problem:

To hoist himself into a tree a 72 Kg man ties one end of a nylon rope of negligible weight around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 358N. Neglect any friction between the rope and the branch and determine the accleration.

Solution

The only force we need concern ourselves with seems to be the vertical motion. A free body diagram shows a downward force of mg, the rope the man pulls on (T1) and an upward force that the rope exerts on the man based on Newtons 3rd law (T2). My dilema is that if the man pulls on the rope, T1, then doesn't part of his weight (mg)get distributed to the force of T1 since they are both in the same direction. Once the man is off the ground then the full downward force would = T1 + mg. Since no friction occurs between the rope and the branch, the sum of the forces T1,mg would = T2.
Sum of all forces = T2 = ma and solving for a= T2/m. Is this the right approach or am I missing something?.
 
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  • #2
I can't exactly follow your reasoning, but here's how I'd approach it.

The only source of tension in the rope is the force that the man applies to it. Think, how much tension would there be if he let go? So T = 358 N. But there are two "legs" to the rope, one pulling up on his waist and one pulling his hands. So the total upward force on the man is 2T. The only downward force is mg. 2T + mg = ma.
 
  • #3
Originally posted by Gameguru My dilema is that if the man pulls on the rope, T1, then doesn't part of his weight (mg)get distributed to the force of T1 since they are both in the same direction.
No, he is pulling down on one end of the rope with force T1. His weight is pulling down on the OTHER end of the rope. because of the "pully" (the turn around the limb) the forces on the man are in opposite directions. While the man is pulling down on one end of the rope, the rope goes around the tree limb so that force is upward on the man. The net force on the man is T1- mg.

Since the man's mass is 72 kg, his weight is 72*9.8= 705.6 Newtons. He is pulling down with force T1= 358 Newtons? He isn't going to go anywhere!
 
  • #4
The net force on the man is T1- mg.

Since the man's mass is 72 kg, his weight is 72*9.8= 705.6 Newtons. He is pulling down with force T1= 358 Newtons? He isn't going to go anywhere!
I don't think so.

If that were true, a 180 lb. man on a 70 lb. scaffold would have to exert more than 250 lb. force to raise himself and the scaffold using a rope and pulley. I don't think most painters can do that.

In gameguru's problem, T pulls upward on the man's hands and on his waist. The only downward force on the man is his weight. So (taking UP to be positive) T = 358 N, mg = -705.6 N.

2T + mg = 716 - 705.6 = 10.4 = ma
a = 10.4/72 = 0.144 m/s^2 upward
 
  • #5
How about using energy conservation to solve this? I like energy conservation.

Work invested into the system by man:
W = F * 2h (factor 2 because of pulley)
Where F is force, h is height.
Potential energy of system:
T = mgh
Where m is mass of man.
Kinetic energy of system:
V = mv2/2
Where v is velocity.

Conservation of energy:
W = T + V
2Fh = mgh + mv2/2
Solve!
v2 = (4F/m - 2g)h
Differentiate!
2va = (4F/m -2g)v
v cancels!
a = 2F/m -g.

I agree with gnome.
 
  • #6
Thanks everyone for the feedback.

The answer appears to be .14 m/s2. Looks like my initial confusion was coming from the fact that the man's weight wa attached to both ends of the rope!

Thanks again.
 

1. What is the definition of acceleration?

Acceleration is the rate of change of an object's velocity over time. It is a vector quantity, meaning it has both magnitude and direction. In simpler terms, acceleration is how fast an object's velocity is changing.

2. How is acceleration calculated?

Acceleration can be calculated by dividing the change in velocity by the change in time. This can be represented by the formula a = (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

3. What is the difference between positive and negative acceleration?

Positive acceleration (also known as acceleration in the forward direction) occurs when an object's velocity is increasing over time. Negative acceleration (also known as deceleration or acceleration in the backward direction) occurs when an object's velocity is decreasing over time. Both positive and negative acceleration can be represented by the same formula, but with different values for velocity.

4. How does the mass of an object affect its acceleration?

The mass of an object does not directly affect its acceleration. However, a heavier object will require more force to accelerate at the same rate as a lighter object. This is because of Newton's second law of motion, which states that force is equal to mass times acceleration (F = ma). Therefore, a larger mass will require a larger force to achieve the same acceleration as a smaller mass.

5. What is the role of friction in determining the acceleration of a rope hoist?

Friction can play a significant role in determining the acceleration of a rope hoist. Friction is a force that opposes motion and can act in the opposite direction of the applied force. In the case of a rope hoist, friction between the rope and the pulley can decrease the acceleration of the hoist. This is because some of the applied force is being used to overcome the friction, rather than accelerating the hoist. Therefore, the amount of friction present can affect the acceleration of a rope hoist.

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