Homework help (angles)

  • Thread starter -Physician
  • Start date
  • #1
85
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Homework Statement


This is the problem:
##a+b=##900 (degrees)
##a=\frac{b}{14}##
Find a and b.



Homework Equations


##a+b=##900 (degrees)
##a=\frac{b}{14}##


The Attempt at a Solution


##a+b=##900
##(\frac{b}{14})+b=##900
##\frac{b + 14b}{14} (14 and 14 get simplified)=## 900
##2b=##900
##b=\frac{90}{2} =##450

Now we have to find a .

##a=\frac{b}{14}=\frac{45}{14}=##3.214285714...(etc)0

Now we need to finish the equation :
##a+b=##900=(3.214285714...+45)0= 48.214285714...0 ≠ 900
I think my mistake is at ##\frac{b+14b}{14}##, because b+14b/14 gives us 15b/14, but i am simplifying because that's the only way(for me) to get to the end.
 

Answers and Replies

  • #2
2,483
100
15b/14=90
Now multiply both sides by 14 and you get:
15b=90*14
To get b divide both sides by 15.

Try practising rearranging equations so you can do them quickly
 
  • #3
85
0
Oh, i knew the problem was there, so that would be :

##a+b=##900
##a=\frac{b}{14}##
##\frac{b}{14} + b =##900
##\frac{15b}{14}=##900
##15b=90 * 14##
##15b=##12600
##b=\frac{1260}{15}=##840
##a=\frac{b}{14}=\frac{84}{14}=##60
##a+b=##900=(6+84)0=900 right?
 
  • #4
2,483
100
Right.
 

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