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Homework help (angles)

  1. Feb 11, 2012 #1
    1. The problem statement, all variables and given/known data
    This is the problem:
    ##a+b=##900 (degrees)
    ##a=\frac{b}{14}##
    Find a and b.



    2. Relevant equations
    ##a+b=##900 (degrees)
    ##a=\frac{b}{14}##


    3. The attempt at a solution
    ##a+b=##900
    ##(\frac{b}{14})+b=##900
    ##\frac{b + 14b}{14} (14 and 14 get simplified)=## 900
    ##2b=##900
    ##b=\frac{90}{2} =##450

    Now we have to find a .

    ##a=\frac{b}{14}=\frac{45}{14}=##3.214285714...(etc)0

    Now we need to finish the equation :
    ##a+b=##900=(3.214285714...+45)0= 48.214285714...0 ≠ 900
    I think my mistake is at ##\frac{b+14b}{14}##, because b+14b/14 gives us 15b/14, but i am simplifying because that's the only way(for me) to get to the end.
     
  2. jcsd
  3. Feb 11, 2012 #2
    15b/14=90
    Now multiply both sides by 14 and you get:
    15b=90*14
    To get b divide both sides by 15.

    Try practising rearranging equations so you can do them quickly
     
  4. Feb 11, 2012 #3
    Oh, i knew the problem was there, so that would be :

    ##a+b=##900
    ##a=\frac{b}{14}##
    ##\frac{b}{14} + b =##900
    ##\frac{15b}{14}=##900
    ##15b=90 * 14##
    ##15b=##12600
    ##b=\frac{1260}{15}=##840
    ##a=\frac{b}{14}=\frac{84}{14}=##60
    ##a+b=##900=(6+84)0=900 right?
     
  5. Feb 11, 2012 #4
    Right.
     
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