# Homework help (angles)

1. Feb 11, 2012

### -Physician

1. The problem statement, all variables and given/known data
This is the problem:
$a+b=$900 (degrees)
$a=\frac{b}{14}$
Find a and b.

2. Relevant equations
$a+b=$900 (degrees)
$a=\frac{b}{14}$

3. The attempt at a solution
$a+b=$900
$(\frac{b}{14})+b=$900
$\frac{b + 14b}{14} (14 and 14 get simplified)=$ 900
$2b=$900
$b=\frac{90}{2} =$450

Now we have to find a .

$a=\frac{b}{14}=\frac{45}{14}=$3.214285714...(etc)0

Now we need to finish the equation :
$a+b=$900=(3.214285714...+45)0= 48.214285714...0 ≠ 900
I think my mistake is at $\frac{b+14b}{14}$, because b+14b/14 gives us 15b/14, but i am simplifying because that's the only way(for me) to get to the end.

2. Feb 11, 2012

15b/14=90
Now multiply both sides by 14 and you get:
15b=90*14
To get b divide both sides by 15.

Try practising rearranging equations so you can do them quickly

3. Feb 11, 2012

### -Physician

Oh, i knew the problem was there, so that would be :

$a+b=$900
$a=\frac{b}{14}$
$\frac{b}{14} + b =$900
$\frac{15b}{14}=$900
$15b=90 * 14$
$15b=$12600
$b=\frac{1260}{15}=$840
$a=\frac{b}{14}=\frac{84}{14}=$60
$a+b=$900=(6+84)0=900 right?

4. Feb 11, 2012