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## Homework Statement

A uniform steel beam of length 5.50 m has a weight of 4.50 103 N. One end of the beam is bolted to a vertical wall. The beam is held in a horizontal position by a cable attached between the other end of the beam and a point on the wall. The cable makes an angle of 25.0° above the horizontal. A load whose weight is 12.0 103 N is hung from the beam at a point that is 4.60 m from the wall.

(a) Find the magnitude of the tension in the supporting cable.

N

(b) Find the magnitude of the force exerted on the end of the beam by the bolt that attaches the beam to the wall.

N

## Homework Equations

torque = Force * distance

sum the vertical forces and set to zero

sum the horizontal forces and set to zero.

sum the moments about any point and set to zero.

ok i seriously am confused how to solve this...cause we just learned about torques..but

EFx = 0

Tcos25 = 0..but this doesnt make sense cause this means that T= 0???

Ffy = 0

Tsin25 - 4.5E3N = 0

then once you get T somehow... and then magically F appears..hmm im soo confused HELP PLEASE!!!!