1. The problem statement, all variables and given/known data A uniform steel beam of length 5.50 m has a weight of 4.50 103 N. One end of the beam is bolted to a vertical wall. The beam is held in a horizontal position by a cable attached between the other end of the beam and a point on the wall. The cable makes an angle of 25.0° above the horizontal. A load whose weight is 12.0 103 N is hung from the beam at a point that is 4.60 m from the wall. (a) Find the magnitude of the tension in the supporting cable. N (b) Find the magnitude of the force exerted on the end of the beam by the bolt that attaches the beam to the wall. N 2. Relevant equations torque = Force * distance sum the vertical forces and set to zero sum the horizontal forces and set to zero. sum the moments about any point and set to zero. ok i seriously am confused how to solve this...cause we just learned about torques..but EFx = 0 Tcos25 = 0..but this doesnt make sense cause this means that T= 0??? Ffy = 0 Tsin25 - 4.5E3N = 0 then once you get T somehow... and then magically F appears..hmm im soo confused HELP PLEASE!!!!