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Homework Help!

  1. Dec 16, 2007 #1
    I am completely lost on this one; An artillery shell is fired at an angle of 85.1 degrees above the horizontal ground with an initial speed of 1960 m/s. The acceleration of gravity is 9.8 m/s/s. Find the total time of flight. Can someone do it and explain how to do it?? Thanks so much!!
     
  2. jcsd
  3. Dec 16, 2007 #2
  4. Dec 16, 2007 #3

    mgb_phys

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    The trick to these questions is that no forces act on the shell horizontally so it is equivalent to a shell fired vertically with a certain velocity.
    You find the vertical componnet of the velocity by drawing a 'force triangle' if the shell goes at 1960m/s at that angle draw a triangle with this as the hypotonuse and the angle given in the question.
     
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