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Homework on forces

  1. Jul 5, 2008 #1
    A 210-kg crate is pushed horizontally with a force of 730N. If the coefficient of the kinetic friction is 0.19, calculate the acceleration of the crate.

    Attempt: FN= 2058

    Force of friction= 391N

    Fnet= Fpush-Ff

    ma= Fpush - Ff
    2058a = 730 - 391


    can anyone check if my answers right, and if im wrong explain how to do it?
  2. jcsd
  3. Jul 5, 2008 #2
    Re: Forces

    ok, first, i assume this is just a typo but you wrote Ff=0.19(391), but Ff = .19*2058, which i assume is 391.
    now more importantly, you say "ma= Fpush - Ff" which is correct but "2058a = 730 - 391" is not. Remember it's m*a for the left part, while you have FN*a
  4. Jul 5, 2008 #3
    Re: Forces

    Simple method:

    Force by push - force by friction = mass of block *acceleration.

    730-.19*(210*9.8) = 210 * a
    >338.98= 210 * a
    >a= 338.98/210= 1.6141 m/s^2
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