1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework on forces

  1. Jul 5, 2008 #1
    A 210-kg crate is pushed horizontally with a force of 730N. If the coefficient of the kinetic friction is 0.19, calculate the acceleration of the crate.

    Attempt: FN= 2058

    Ff=0.19(391)
    Force of friction= 391N

    Fnet= Fpush-Ff

    ma= Fpush - Ff
    2058a = 730 - 391

    a=339/2058

    can anyone check if my answers right, and if im wrong explain how to do it?
     
  2. jcsd
  3. Jul 5, 2008 #2
    Re: Forces

    ok, first, i assume this is just a typo but you wrote Ff=0.19(391), but Ff = .19*2058, which i assume is 391.
    now more importantly, you say "ma= Fpush - Ff" which is correct but "2058a = 730 - 391" is not. Remember it's m*a for the left part, while you have FN*a
     
  4. Jul 5, 2008 #3
    Re: Forces

    Simple method:

    Force by push - force by friction = mass of block *acceleration.

    730-.19*(210*9.8) = 210 * a
    >338.98= 210 * a
    >a= 338.98/210= 1.6141 m/s^2
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Homework on forces
  1. Forces - Homework (Replies: 4)

Loading...