- #1
Larrytsai
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A 210-kg crate is pushed horizontally with a force of 730N. If the coefficient of the kinetic friction is 0.19, calculate the acceleration of the crate.
Attempt: FN= 2058
Ff=0.19(391)
Force of friction= 391N
Fnet= Fpush-Ff
ma= Fpush - Ff
2058a = 730 - 391
a=339/2058
can anyone check if my answers right, and if I am wrong explain how to do it?
Attempt: FN= 2058
Ff=0.19(391)
Force of friction= 391N
Fnet= Fpush-Ff
ma= Fpush - Ff
2058a = 730 - 391
a=339/2058
can anyone check if my answers right, and if I am wrong explain how to do it?