A particle passes through the origin with an initial speed of 5.6 m/s in the positive y direction. The particle accelerates in the negative x direction at 5.2 m/s2.(adsbygoogle = window.adsbygoogle || []).push({});

(a) What are its x and y positions after 4.0 s?

m (x position)

m (y position)

(b) What are vx and vy at this time?

m/s (vx)

m/s (vy)

This question seems pretty hard to me, I have tried about 4 times to get the answer to no avail, heres what I have done.

To try and find out where its x and y positions were after 4.0 seconds, I plugged it into the Position Versus Time Equation, xf=xi+vixt+.5axt^2

Since I have the givens

time = 4.0

Vi=5.6

a=-5.2^2

I plug it into the equation.

xf=xi+vixt+.5axt^2

xf=0+5.6(4)+.5(-5.2)^2(4.0)^2

xf=238.72

however, this answer for part A. was not correct.

Can anyone tell me what I am doing wrong here?

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# Homework, Particle Question

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