# Homogeneous system of linear equation:

TonyC
I am having trouble finding the solution to the homogeneous system of linear equations:
2x-2y+z=0
-2x+y+z=0

TonyC
I guess I should have also put:

How can I break this down?

Perhaps I have been out of the rigid math stuff for a while, but how are you going to solve a system with three unknowns and only two equations?

Homework Helper
Choose one variable (e.g. z) as "t" and solve the system for x and y in function of t.
You'll get an infinite number of solutions, for every t (so z), you have a couple (x,y).

TonyC
Hence my problem..
The answers to choose from are:
x=3/4t, y=-t,z=1/2t
x=-3/4t,y=-t,z=1/2t
z=-3/4t,y=t,z=1/2t
z=3/4t,y=t,z=1/2t

This is why I am stumped.

Homework Helper
In your case, y was substituted for t. Then solve it as if t was a parameter for x and z.

TonyC
? I am still confused.

Homework Helper

$$\left\{ \begin{gathered} 2x - 2y + z = 0 \hfill \\ - 2x + y + z = 0 \hfill \\ \end{gathered} \right$$

Substitute y = t, t is now a parameter, and solve the following (2x2)-system for x and z

$$\left\{ \begin{gathered} 2x + z = 2t \hfill \\ - 2x + z = - t \hfill \\ \end{gathered} \right$$