Homogeneous system

  • Thread starter cupu
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  • #1
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Hello,

In a book I'm reading about linear algebra it's mentioned that in order for the homogeneous system
Ax = 0
to have a solution (other than the trivial solution) the coefficient Matrix must be singular.
The thing is, I can't remember (the wikipedia page on homogeneous systems didn't turn up anything) why if A is invertible, then the system does not have non-zero solutions.

Any help on why this is so is appreciated.

Thank you in advance
 
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Answers and Replies

  • #2
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If A is invertible, then A-1 exists.
Ax = 0 ==> A-1Ax = A-10 = 0 ==> x = 0

Another way to look at it is that, for A-1 to exist, both it and A must be one-to-one. The equation Ax = 0 obviously has at least one solution, x = 0, but the one-to-oneness prevents it from having any additional solutions.
 
  • #3
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That makes sense, thank you very much for the response Mark44.
 

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