Well heres the question: Find 'X' where 'AX = ' 6 8 4 and 'A = ' 1 2 4 3 1 2 0 2 4 Now i would go ('AX')*('A^-1') which would clearly give me 'X' BUT 'A' is not invertible! So how do i do this? (by the way the ' is not part of the question). And then it says find the null vectors of A and hence the general solution. what do i do here?