- #1

- 4

- 0

Mass(kg) Spring Length(cm)

0.0 15.7

1.0 16.5

2.0 17.8

3.0 19.3

and so on...

How do I determine whether or not the spring is obeying Hooke's law?

I'm not sure what k is equal too.

And is 15.7 the equilibrium?

- Thread starter audreylynn
- Start date

- #1

- 4

- 0

Mass(kg) Spring Length(cm)

0.0 15.7

1.0 16.5

2.0 17.8

3.0 19.3

and so on...

How do I determine whether or not the spring is obeying Hooke's law?

I'm not sure what k is equal too.

And is 15.7 the equilibrium?

- #2

Born2bwire

Science Advisor

Gold Member

- 1,779

- 18

- #3

- 259

- 3

[tex]F=k(y_{0}-y)-mg[/tex]

Where y_{0} is the point of equilibrium. g= 9.8 m/sec^2 (gravitational constant), m is the mass

, and y is the measured length of the spring.

If the force is zero, i.e., the mass is in equilibrium,

[tex]k(y_{0}-y)-mg=0[/tex]

Plug in the possible values for m and and y and if the equations are consistent(with y_{0}, and k being the unknowns), then hook's law is obeyed.

- #4

- 648

- 2

If it is a straight line then Hooke's Law is obeyed. The gradient is equal to the elastic constant, k.

- Last Post

- Replies
- 6

- Views
- 3K

- Last Post

- Replies
- 3

- Views
- 3K

- Last Post

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 21K

- Last Post

- Replies
- 3

- Views
- 462

- Last Post

- Replies
- 1

- Views
- 1K

- Last Post

- Replies
- 8

- Views
- 5K

- Last Post

- Replies
- 6

- Views
- 80K