I dont know anything about diff eq but:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] F = ma = -kx(t) [/tex]

[tex] a = \frac{d^2(x)}{dt^2} [/tex]

[tex] -kx(t) = m\frac{d^2(x)}{dt^2} [/tex]

So we need a function whos second derivative is the same as the function itself.

I know hooke's law says the function is [tex] cos(\omega t) [/tex] but I dont see why [tex] e^x [/tex] doesnt satisfy the original condition.

Can anyone shed some light?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Hooke's Law function

**Physics Forums | Science Articles, Homework Help, Discussion**