I dont know anything about diff eq but:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] F = ma = -kx(t) [/tex]

[tex] a = \frac{d^2(x)}{dt^2} [/tex]

[tex] -kx(t) = m\frac{d^2(x)}{dt^2} [/tex]

So we need a function whos second derivative is the same as the function itself.

I know hooke's law says the function is [tex] cos(\omega t) [/tex] but I dont see why [tex] e^x [/tex] doesnt satisfy the original condition.

Can anyone shed some light?

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# Hooke's Law function

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