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Hooke's Law problem

  1. Oct 1, 2009 #1
    1. The problem statement, all variables and given/known data
    A 2kg mass and a 3kg mass are on a horizontal frictionless surface, connected by a massless spring with spring constant k=136N/m. An 18 N force is applied to the larger mass. How much does the spring stretch from its equilibirum length? (answer in cm)

    2. Relevant equations
    F=-kd
    k= 136N/m
    F=18N


    3. The attempt at a solution
    I did the obvious, I used the equation above and solved for D: 18/136 = 0.132m x 100= 13.2 cm, which is wrong. I obviously neglected the two masses, which is probably where I went wrong? Can anyone help me out by providing the proper equation and solution?
     
  2. jcsd
  3. Oct 1, 2009 #2
    Did you try drawing a free body diagram of the two mass strings connected by a massless string? It might be easier for you to write down your equations for this problem after you draw the free body diagram. Do you agree that the spring force and the applied force make up the net force?
     
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