A block attached to a spring (which is attached to a wall) lies on a horizontal frictionless surface, and the spring constant is 50 N/m. Initially, the spring is at its relaxed length and the block is stationary at position x = 0. Then an applied force with a constant magnitude of 3.0 N pulls the block in the positive direction of the x axis, stretching the spring until the block stops. When that stopping point is reached, what is the position of the block? I tried using Hooke's Law: 3.0 = 50x x = 3.0/50 x = 0.06 m However, when I checked my answer, it said x = 0.12 m. Does anyone know what I did wrong? Thank you!