1. The problem statement, all variables and given/known data A 1.50 kg ball and a 2.00 kg ball are glued together with the lighter one below the heavier one. The upper ball is attached to a vertical ideal spring of force constant 165 N/m and the system is vibrating vertically with amplitude 15.0 cm. The glue connecting the balls is old and weak, and it suddenly comes loose when the balls are at the lowest position in their motion. Find the amplitude of the vibrations after the lower ball has come loose. 2. Relevant equations ΣF=ma W=mg Fs=-kx m1=1.5kg m2=2kg 3. The attempt at a solution ∑F=ma -kx1-(m1+m2)g=0 x1=(m1+m2)g/k x1= .2079m .15m+x1=.3579m x2=(m2)g/k x2=.11879m .3579m - .11879m = .239m Even after solving it, I do not really understand what is going on in the problem. Why is x=.2079 with both of them attached, when the amplitude is .15m?