Hookes law

  • Thread starter jamexd
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  • #1
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Homework Statement


A mass of 2.3 kg is dropped from a height of 4.82 meters above a vertical spring anchored at its lower end to the floor. If the spring constant is 20 N/cm, how far, to the nearest tenth of a cm, is the spring compressed?
answer is 34.1

Homework Equations


PE = mgh
KE = (1/2)m(v^2)
Hookes Law= (1/2)K(x^2)



The Attempt at a Solution


mgh = (1/2)K(x^2)
 
Last edited:

Answers and Replies

  • #2
Pengwuino
Gold Member
5,009
16
There you go, that is how you solve the equation. The actual solution, however, is wrong. Did you keep your units?
 

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