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**hoop and disk rolling(help plz)**

ok i've been looking at this forever and cant get it...dont know what to do..i would appreciate it if someone could help

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A uniform solid disk and a uniform hoop are

placed side by side at the top of an incline of

height h.

If they are released from rest and roll with-

out slipping, determine their speeds when

they reach the bottom. (here i found the speeds to be

velocity disk = sqrt(4/3hg)

velocity hoop = sqrt(hg)

now here is my problem

What is the ratio of their accelerations as they

roll down the incline, a_disk / a_hoop?

1. 4/3

2. 2

3. sqrt(3)

4. sqrt(3/2)

5. 1/2 xxxx

6. sqrt(4/3)

7. 1/3 xxxx

8. 3

9. 3/2

10. sqrt(2)

..ps - the ones i put an xxxx out the right on i figured couldnt be it since the velocity of the disk is greater the acceleration of the disk(top value) must be greater