Horizontal Circular Motion

  • #1

Homework Statement


A microwave's turntable spins 3.0 revolutions per minute. It has a 250.0g cup of coffee placed 15.0cm from its centre. Find its period of revolution, its tangential velocity and the centripetal force on the cup.

2. The attempt at a solution
period of revolution [tex]\frac{{60}}{3} = 20[/tex] seconds
tangential velocity [tex]\frac{{2\pi r}}{T} = \frac{{2\left( \pi \right)\left( {15} \right)}}{{20}} = 4.7123\,m\,s^{ - 1} [/tex]
centripetal force [tex]\frac{{mv^2 }}{r} = \frac{{0.25\left( {\frac{{2\left( {15} \right)\left( \pi \right)}}{{20}}} \right)}}{{15}} = 0.0785\,N[/tex] towards the centre of the circle


I was wondering if somebody could kindly take the time to look over my working and see if it is correct. Thank you greatly for your time and effort.
unique_pavadrin
 

Answers and Replies

  • #2
340
0
I didnt check the numbers but the rest looks okay. What is providing the centripetal force here?
 
  • #3
the centripetal force is provided by the spinning turntable of the microwave if I'm not mistaken.
 
  • #4
22
0
i presumed it is friction that is providing the centripetal force.....
 
  • #5
friction of.....
 

Related Threads on Horizontal Circular Motion

  • Last Post
Replies
1
Views
698
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
4
Views
4K
  • Last Post
Replies
3
Views
9K
  • Last Post
Replies
1
Views
3K
Replies
5
Views
243
Replies
4
Views
10K
Replies
4
Views
3K
Replies
4
Views
4K
Replies
9
Views
1K
Top