# Horizontal Circular Motion

## Homework Statement

A microwave's turntable spins 3.0 revolutions per minute. It has a 250.0g cup of coffee placed 15.0cm from its centre. Find its period of revolution, its tangential velocity and the centripetal force on the cup.

2. The attempt at a solution
period of revolution $$\frac{{60}}{3} = 20$$ seconds
tangential velocity $$\frac{{2\pi r}}{T} = \frac{{2\left( \pi \right)\left( {15} \right)}}{{20}} = 4.7123\,m\,s^{ - 1}$$
centripetal force $$\frac{{mv^2 }}{r} = \frac{{0.25\left( {\frac{{2\left( {15} \right)\left( \pi \right)}}{{20}}} \right)}}{{15}} = 0.0785\,N$$ towards the centre of the circle

I was wondering if somebody could kindly take the time to look over my working and see if it is correct. Thank you greatly for your time and effort.

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I didnt check the numbers but the rest looks okay. What is providing the centripetal force here?

the centripetal force is provided by the spinning turntable of the microwave if I'm not mistaken.

i presumed it is friction that is providing the centripetal force.....

friction of.....