Consider a Horizontal light clock of length ##L_0## lying at rest in a frame K. There are two important events: (A) a photon gets emitted from the left mirror and (B) it gets reflected at the right mirror.(adsbygoogle = window.adsbygoogle || []).push({});

Another frame K' is moving by at velocity v and the frames are in standard configuration such that event (A) is assigned coordinates ##(t_A,x_A) = (t'_A,x'_A) = (0,0)##. Clearly, ##t_B = L_0## (c=1), but now the question is, what is ##t_B'##?

My intuitive reasoning would be as follows: in K' the length of the light clock is contracted to a length of ##L_0/\gamma## and photon has the same velocity c=1. But now the right mirror is moving towards the photon at velocity v, and hence it takes a time

$$t_B' = \frac{L_0}{\gamma (1-v)}$$

for the photon to reach the right mirror.

However, according to

exercise 4 at p. 24 in http://www.uio.no/studier/emner/matnat/astro/AST1100/h14/undervisningsmateriale/lecture7.pdf

the answer should be

$$t_B' = L_0 \gamma(1-v).$$

So, where am I going wrong in my argument?

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# Horizontal light clock

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