A 280000-kg wood block is firmly attached to a very light horizontal spring, as shown in the figure . The block can slide along a table where the coefficient of friction is 0.30. A force of 22 N compresses the spring .18m . If the spring is released from this position, how far beyond its equilibrium position will it stretch at its first maximum extension? I used 1/2 kx^2 = mew mg(x+D) D is the distance the block travels D= ((2*mew*mg)/k) -x didnt come up with the right answer and I dont know why..Please help??