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Introductory Physics Homework Help
Horizontal velocity over an uneven surface
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[QUOTE="BvU, post: 4955535, member: 499340"] In this case the ball isn't falling, but sliding. The surface exercises a normal force on the ball that is directed perpendicular to the surface (hence the name normal). That normal force has a non-zero horizontal component, so it increases v when the ball goes down, and it slows the thing down when going uphill. Roller coaster physics ! (Of course, at Q the normal force is straight up again). [/QUOTE]
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Introductory Physics Homework Help
Horizontal velocity over an uneven surface
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