- #1
NotMrX
- 97
- 0
Hello,
This problem has been messing me up.
A person waters their yard. He has a rubber hose cylinder with an inner radius,[tex]R_i[\tex], of 1.5 cm and an outer radius, [tex]R_o[/tex], of 1.7 cm. The thermal conductivity of of rubber is 0.2 in SI units. The hose is 5 meters long, L. The hose is completely in the air with a temp of 30 Celsius while the water has a temp of 20 Celsius. Ignoring the heat loss from the end what is the power or heat loss per second.
Here is my attempt:
[tex]P=K*A\frac{\DeltaT}{r}[/tex]
[tex]dA=L*2*\pi*dr[/tex]
[tex]P=K\frac{\DeltaT}{r}L*2*\pi*dr[/tex]
[tex]P=k*2*\pi*\DeltaT*L*Ln\frac{R_o}{R_i}[/tex]
It seems like something is wrong though.
This problem has been messing me up.
A person waters their yard. He has a rubber hose cylinder with an inner radius,[tex]R_i[\tex], of 1.5 cm and an outer radius, [tex]R_o[/tex], of 1.7 cm. The thermal conductivity of of rubber is 0.2 in SI units. The hose is 5 meters long, L. The hose is completely in the air with a temp of 30 Celsius while the water has a temp of 20 Celsius. Ignoring the heat loss from the end what is the power or heat loss per second.
Here is my attempt:
[tex]P=K*A\frac{\DeltaT}{r}[/tex]
[tex]dA=L*2*\pi*dr[/tex]
[tex]P=K\frac{\DeltaT}{r}L*2*\pi*dr[/tex]
[tex]P=k*2*\pi*\DeltaT*L*Ln\frac{R_o}{R_i}[/tex]
It seems like something is wrong though.
Last edited: