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Hot cylinder, bowl of water

  1. Sep 2, 2008 #1
    1. The problem statement, all variables and given/known data
    A 150 g copper bowl contains 220 g of water, both at 20C. A very hot 300 g copper cylinder is dropped into the water, causing the water to boil, with 5.00 g being converted to steam. The final temperature of the system is 100C. Neglect energy transfers with the environment. (a) How much energy (incalories) is transferred to the water as heat? (b) How much to the bowl? (c) What is the original temperature of the cylinder?


    2. Relevant equations
    Q=C(delta)T
    Lv = 539cal/g



    3. The attempt at a solution
    Q=(1cal/g*k)(220g)(80k) = 17.6 kcal
    Lv = 539cal/g 539cal/g(5) =2.69kcal
    a)Q water = 17.6 + 2.69 = 20.3 Kcal
    b)Q = (.0923/g*k) (150g) (80k) = 1.11 K cal
    c) Not sure.
     
  2. jcsd
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