(adsbygoogle = window.adsbygoogle || []).push({}); A particle of mass 12 grams moves along the x axis. It has a restoring force F= -0.06 N/m. If it starts from x=10 cm with a speed of 20 cm/sec toward the equilibrium position, Find its amplitude, period, and frequency. Determine when the particle reaches the equilibrium point for the first time.

Edit:

I solved the question this way:

F= -w^2*m -> w=1/2(sqroot)

v=x*w

20=x*1/2(sqrt)

x=28.2

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T=2pi/w -> T=8.8

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a(accelaration) = -w^2*x

a= -14,1

Vf=Vi+a.t

t=1,141 sec.

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2nd way- and some one else solved the question with this way :

Let w = angular frequency, A = amplitude, T = time period

Acceleration = F / m = 0.06 / 0.012 = 5 m/s^2

Acc = w^2 * x

w^2 * 0.10 = 5

Simplifying, w = 5 (sqrt 2)

T = 2 pi / w

m * v^2 + m *w^2* x^2 = m* w^2 * A^2

0.04 + 0.5 = 50 * A ^2

A = (sqrt 1.08) / 10 m = sqrt 1.08 * 10 cm

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and I'M confused :(

Thanks,..

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# Homework Help: Hot Oscillation question

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