(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A house is built on the top of a hill with a nearby 45° slope (Fig. 6-19). An engineering study indicates that the slope angle should be reduced because the top layers of soil along the slope might slip past the lower layers. If the static coefficient of friction between two such layers is 0.67, what is the least angle through which the present slope should be reduced to prevent slippage?

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2. Relevant equations

f = μn

f = mg*sin ∅

n = mg*cos ∅

Current value of ∅ = 45°

μ = 0.67

3. The attempt at a solution

I drew a free body diagram, and found that the friction force is equal and opposite that of mg*sin∅, and that the normal force was mg*cos∅.

I then set up this equation:

Net force = f - mg*sin∅

μ*n - mg*sin∅ = 0

μ*n = mgsin∅

μ*mgcos∅ = mgsin∅

(mg's cancel)

μ * cos ∅ = sin ∅

μ = tan ∅

tan^{-1}μ = ∅

I plugged in 0.67 for mu, and got 33.822°, which I am being told is wrong.

Can somebody please help me!?! I have one more submission left.

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# Homework Help: House on a Hill slope problem

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