# How am I wrong ?

#### Joe91090

How am I wrong ??

1. The problem statement, all variables and given/known data

A child rides a sled down a hill that desends at an angle of 27.1 degrees to the horizontal. The is 23.1m long.

A) what is the horizontal component of the childs displacement
B) what is the vertical component of the childs displacement

2. Relevant equations

SOH CAH TOA

3. The attempt at a solution

I Found the horizontal component is 20.56m is correct by cos27.1 x 23.1 but when I submitt my answer of 10.53 for the vertical by sin27.1 x 23.1 it says im wrong.

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#### gabbagabbahey

Homework Helper
Gold Member
Re: How am I wrong ??

but when I submitt my answer of 10.53 for the vertical by sin27.1 x 23.1 it says im wrong.
The child slides down the hill

#### flatmaster

Re: How am I wrong ??

Make sure you're not doing Sin[27.1x23.1]. Also, double check your calculater is in degree mode

#### gabbagabbahey

Homework Helper
Gold Member
Re: How am I wrong ??

More specifically you need to account for the acceleration down the slope.
Are you sure about that? Does the final displacement really depend on how fast the child gets there?

#### Joe91090

Re: How am I wrong ??

I dont know how knowing the direction the child is moving matters. The child still moves 10.53m vertically.

#### gabbagabbahey

Homework Helper
Gold Member
Re: How am I wrong ??

I dont know how knowing the direction the child is moving matters.
Upwards is positive, so downwards is____?

#### Joe91090

Re: How am I wrong ??

wow. so simple thank you very much

#### gabbagabbahey

Homework Helper
Gold Member
Re: How am I wrong ??

wow. so simple thank you very much
No problem; but remember direction always matters when dealing with vectors.

#### tacosareveryyum

Re: How am I wrong ??

Are you sure about that? Does the final displacement really depend on how fast the child gets there?
Yeah I miss read the question and edited my post immediately after posting it......

"How am I wrong ?"

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